Sticker Math

📊 Your Collection

unique stickers owned out of 980

0 490 980

Unique stickers

Duplicates you have

Optional — used to calculate what you've already spent

Currency

Price per pack

Pack prices vary by retailer — check yours for the most accurate result

Running 10,000 simulated collection journeys…

This uses the Coupon Collector's Problem

📈 Your Progress

0 / 670 stickers

🆕

Fresh Out The Wrapper

Every single pack right now is giving you new stickers.

🎯 Your Three Scenarios 10k simulations

🍀

Lucky

1 in 10 collectors

—

— more packs

— total spend

📊

Expected

most likely outcome

—

— more packs

— total spend

😱

Nightmare

1 in 10 collectors

—

— more packs

— total spend

💡 The Numbers

—

stickers still needed

—

expected packs to buy

—

of packs give new stickers

—

effective cost per new sticker

Cost breakdown

Already spent (est.)	—
Expected additional packs	—
Panini direct order (last 50)	—
Expected total (from pocket to completion)	—

📱 Share Your Result

🧮 How the Maths Works

This tool is built on the Coupon Collector's Problem — a classic probability model. When you already own k unique stickers from an album of N total, the chance that your next random sticker is new is (N − k) / N.

Getting from sticker k to k+1 follows a geometric distribution. We simulate this 10,000 times end-to-end using a technique called Monte Carlo simulation, giving you statistically accurate lucky, expected, and nightmare percentiles — not rough guesses.

The simulation assumes stickers are distributed uniformly at random. In practice, Panini may print some stickers in greater quantities, which can make the real distribution slightly harder or easier than predicted.